Snovv wrote:
i is complex (i = squareroot of -1).
You'd think i^i is about as complex as you can get but i^i is real.
You'd think i^i is about as complex as you can get but i^i is real.
^^
Is what we hear during Razorgore
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| Author: | Samelina [ Wed Nov 02, 2005 5:32 pm ] |
| Post subject: | Poor Ropetown |
Going to be invaded with Blood Elf apps |
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| Author: | flipoit [ Wed Nov 02, 2005 5:33 pm ] |
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deleting my priest and going blood elf! |
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| Author: | Snovv [ Thu Nov 03, 2005 2:13 am ] |
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i is complex (i = squareroot of -1). You'd think i^i is about as complex as you can get but i^i is real. |
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| Author: | Samelina [ Thu Nov 03, 2005 8:49 am ] |
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Snovv wrote: i is complex (i = squareroot of -1).
You'd think i^i is about as complex as you can get but i^i is real. ^^ Is what we hear during Razorgore
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| Author: | malice [ Thu Nov 03, 2005 12:22 pm ] |
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wasnt i imaginary? just like alliance guilds making it past broodlord? |
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| Author: | Kruxx [ Thu Nov 10, 2005 9:53 pm ] |
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malice wrote: wasnt i imaginary? just like alliance guilds making it past broodlord?
he wins, something complex is real and imaginary together. u lose. :p |
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| Author: | Snovv [ Fri Nov 11, 2005 3:12 pm ] |
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Kruxx wrote: malice wrote: wasnt i imaginary? just like alliance guilds making it past broodlord? he wins, something complex is real and imaginary together. Actually real and imaginary numbers are a subset of complex numbers (this is similar to how squares are a subset of rectangles; all squares are rectangles but not all rectangles are squares). In other words all real numbers are also complex (with their imaginary parts = 0) and all imaginary numbers are also complex (with their real parts = 0). However not all complex numbers are real and not all complex numbers are imaginary. So the original statement "i is complex" is correct. The second statement "You'd think i^i is about as complex as you can get but i^i is real" is perhaps a bit misleading or awkward (what does it mean for one number to be more complex than another?). However it is also still a correct statement. Regardless, proving that i^i is a real number is much more interesting than arguing about semantics. One way to show this (which happens to be the way I did) involves using Euler's formula e^ix = cos(x) + isin(x). |
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| Author: | Shadowcast[LGN] [ Fri Nov 11, 2005 3:17 pm ] |
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Snovv wrote: I am totally gay. Thanks for the clarification. 
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| Author: | Lyra [ Fri Nov 11, 2005 4:24 pm ] |
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The MIT student strikes again! |
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| Author: | shiv_ [ Sat Nov 12, 2005 12:47 am ] |
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coulda sworn i learned that in 10th grade... seriously. |
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| Author: | Vidar [ Sat Nov 12, 2005 12:54 am ] |
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Quote: proving that i^i is a real number is much more interesting than arguing about semantics. One way to show this (which happens to be the way I did) involves using Euler's formula e^ix = cos(x) + isin(x).
Proving things is what made me quit computer science. My god is that crap wretched and mind numbing. |
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| Author: | Stabby [ Sat Nov 12, 2005 2:56 pm ] |
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Vidar wrote: Proving things is what made me quit computer science. My god is that crap wretched and mind numbing. I'm in the same boat as you then 
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